Fizzbuzz Challenge

Fizzbuzz is a popular challenge for all types of programming languages. It is a simple challenge that tests your ability to use control structures. You will use loops and conditionals to solve this challenge.

1. Write a program that prints the numbers from 1 to 100.
2. For multiples of 3 print “Fizz” instead of the number
3. For the multiples of 5 print “Buzz”.
4. For numbers which are multiples of both 3 and 5 print “FizzBuzz”.

Hints

• You can use the modulus operator to check if a number is divisible by another number.
• You can echo <br> tag to add a line break after each number.

Click For Solution

for ($i = 1; $i <= 100; $i++) {
    if ($i % 3 === 0 && $i % 5 === 0) {
        echo 'FizzBuzz';
    } elseif ($i % 3 === 0) {
        echo 'Fizz';
    } elseif ($i % 5 === 0) {
        echo 'Buzz';
    } else {
        echo $i;
    }

    echo '<br>';
}

We can shorten it a little by using % 15 instead of % 3 and % 5.

for ($i = 1; $i <= 100; $i++) {
    if ($i % 15 === 0) {
        echo 'FizzBuzz';
    } elseif ($i % 3 === 0) {
        echo 'Fizz';
    } elseif ($i % 5 === 0) {
        echo 'Buzz';
    } else {
        echo $i;
    }

    echo '<br>';
}